(64-x^2)/(x^2+8x)=-1

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Solution for (64-x^2)/(x^2+8x)=-1 equation: 


D( x )

x^2+8*x = 0

x^2+8*x = 0

x^2+8*x = 0

x^2+8*x = 0

DELTA = 8^2-(0*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)-8)/(1*2) or x = (-64^(1/2)-8)/(1*2)

x = 0 or x = -8

x in (-oo:-8) U (-8:0) U (0:+oo)

(64-x^2)/(x^2+8*x) = -1 // + 1

(64-x^2)/(x^2+8*x)+1 = 0

x^2+8*x = 0

x^2+8*x = 0

x*(x+8) = 0

x+8 = 0 // - 8

x = -8

x*(x+8) = 0

(64-x^2)/(x*(x+8))+1 = 0

(64-x^2)/(x*(x+8))+(1*x*(x+8))/(x*(x+8)) = 0

1*x*(x+8)-x^2+64 = 0

8*x+64 = 0

(8*x+64)/(x*(x+8)) = 0

(8*x+64)/(x*(x+8)) = 0 // * x*(x+8)

8*x+64 = 0

8*x+64 = 0 // - 64

8*x = -64 // : 8

x = -64/8

x = -8

x in { -8} 

x belongs to the empty set

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